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orAClE 根据里面字段的日期统计出每月总金额的sql...

oracle 根据里面字段的日期统计出每月总金额的sql语句怎么写在线等 如果是date型 1 2 3 select to_char(createtime,'yyyymm'),sum(totacaccount) from 表名 where to_char(createtime,'yyyy')=to_char(sysdate,'yyyy') group by to_char(createt...

select * from (select 日期,时间,字段a,字段b,其他字段 from table_name order by 日期 desc,时间 desc ) where rownum

参考思路: 1、SQL语句条件:“当前月” - “数据表中存储的月份” > 3 2、“当前月”:利用Oracle的内置时间函数 3、“数据表中存储的月份”: (1)如果是单独一个字段存储的月份,直接访问该月份字段 (2)如果是使用一个字段存放的日期,需要利用内...

还有这么到的???2015-09-01到2014-09-12 select date,count(*) as number from table_name where date = '2015-09-01' union select date,count(*) as number from table_name where date = '2015-09-02' 如果天数比较少 可以这么干,如果比...

使用Months_between(f,s) 日期f和s间相差月数,但结果有小数。你要整数,可以进行截龋 实例: SELECT Months_between(SYSDATE,input_date) FROM aa_yudy_deal

WITH TT AS (SELECT 1 AS ID , 15 AS COUNTNUM FROM DUAL UNION ALLSELECT 2 AS ID , 12 AS COUNTNUM FROM DUAL UNION ALLSELECT 3 AS ID , 11 AS COUNTNUM FROM DUAL UNION ALLSELECT 4 AS ID , 16 AS COUNTNUM FROM DUAL UNION ALLSELECT 5 AS...

考勤信息表 tbl_manualsign ( ms_id user_id ms_time ms_desc ms_tag ) 光靠这一个表,不能确定你需要的信息埃 比如迟到次数,早退次数,还需要知道上下班的时间啊(是固定的值吗) 旷工次数,需要知道哪此是工作日啊(也是固定值,还是按常规算...

你首先要确定你的环境变量里日期格式是什么样的,是yyyy/mm/dd还是yyyy-mm-dd,然后把两个格式化成一种就可以了,而且也不需要to_char。对于你的问题最简单的改法就是between to_char(trunc(sysdate,'MM'),'yyyymmdd') and '20150601' 但不是最...

SELECT Customer ,SUM(Amount) FROM TableX GROUP BY Customer

Select 地点, Count(*) 总次数, Sum(Case When 状态='Yes' then 1 else 0 end) 正常, Sum(Case When 状态='No' then 1 else 0 end) 不正常From 表1Where 时间 Between '2016-06-01' And '2016-06-30'Group By 地点

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